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worty [1.4K]
3 years ago
8

Slope is -2 and (-1,7) is on the line ; standard form

Mathematics
1 answer:
irinina [24]3 years ago
4 0

Answer:

y=-2x+5

Step-by-step explanation:

y=-2x+b

7=2+b

b=5

Therefore, y=-2x+5

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Melissa notes that her savings account earned $54.93 in nine months. If the
djyliett [7]

Answer:

$135.63

Step-by-step explanation:

first and foremost, the formula for interest is I = Prt. P is the principal, r is the rate, and t is the time.

so plug in the numbers you have. Always convert the rate to a decimal. The rate would be 0.0.45. Plug in 54.93 for the I and plug in 9 for the time. It would look like this:

54.93 = P(0.045)(9) --> 54.93 = 0.405P --> P = 135.63

4 0
4 years ago
The equation p=100−5t represents the percent p of battery power remaining in a tablet after t hours.
puteri [66]

Answer:

20

Step-by-step explanation:If p=100% and t=20% than 5×20=100 because if you add 20 five different times you get 100.

7 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
uysha [10]

Answer:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926

And we are 9% confidence that the true mean for the difference of the population means is given by:

0.0743 \leq \mu_1 -\mu_2 \leq 1.926

Step-by-step explanation:

For this problem we have the following data given:

\bar X_1 = 9 represent the sample mean for one of the departments

\bar X_2 = 8 represent the sample mean for the other department

n_1 = 25 represent the sample size for the first group

n_2 = 20 represent the sample size for the second group

s_1 = 2 represent the deviation for the first group

s_2 =1 represent the deviation for the second group

Confidence interval

The confidence interval for the difference in the true means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

The confidence given is 95% or 9.5, then the significance level is \alpha=0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df=n_1 +n_2 -2= 20+25-2= 43

And the critical value for this case is t_{\alpha/2}=2.02

And replacing we got:

(9-8) -2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 0.0743

(9-8) +2.02 \sqrt{\frac{2^2}{25} +\frac{1^2}{20}}= 1.926

And we are 9% confidence that the true mean for the difference of the population means is given by:

0.0743 \leq \mu_1 -\mu_2 \leq 1.926

4 0
3 years ago
The residuals for data set A and data set B were calculated and plotted on separate residuals plots. If neither the residuals fo
Oliga [24]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the 12th term of the geometric sequence.<br> 15, 30, 60, ...
nikklg [1K]
⇒ common ratio =r=3 and the given sequence is geometric sequence. Where an is the nth term, a is the first term and n is the number of terms. ⇒ 12th term is 708588 . ⇒Sum=1062880 .
3 0
3 years ago
Read 2 more answers
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