Option D
Money earned by Marty is $ 16.72
<em><u>Solution:</u></em>
Given that, Marty started a lawn mowing business
He kept track of his expenses and earnings in a table
Lawn Mower = - $49.99
Gasoline = - $8.79
Moyer's yard = $ 40
Griffen's yard = $ 35.50
To find: Money earned by Marty
Total money earned = lawn mower + gasoline + moyers yard + griffens yard
Total money earned = -49.99 - 8.79 + 40 + 35.50
Total money earned = -58.78 + 40 + 35.50
Total money earned = -18.78 + 35.50 = 16.72
Thus money earned by Marty is $ 16.72
Answer:
E started with 26 books, sold 13 books, bought 17 more books, and ended with 30 books
Step-by-step explanation:
E has _ books: x
E Sells 1/2 of that _ books: x/2
E buys 17 books and now had 30: (x/2) + 17 = 30
30 - 17 = 13
13 x 2 = 26
x/2 = 26
13 + 17 = 30 <-- checking work
My guess is that x = 13
You didn't clarify what exactly you are looking for but I hope this helps clarify some steps of the problem anyway!
Answer:
yes becuse id theres 4 letters it can be a parallogram
To graph the line we need two points; we already have one the point (4,2) now we need to find another one; to do this we get the equation of the line given by:

where m is the slope and (x1,y1) are a point throught the line. Plugging the values given we have:

Now we give a value to x and find the corresponding y. If x=0, then:

hence we have the point (0,-2).
Now that we have two points (0,-2) and (4,2) we graph them on the plane and join them with a straight line, hence the graph is:
Taking

and differentiating both sides with respect to

yields
![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B3x%5E2%2By%5E2%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B7%5Cbigg%5D%5Cimplies%206x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D0)
Solving for the first derivative, we have

Differentiating again gives
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B6x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B0%5Cbigg%5D%5Cimplies%206%2B2%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%2B2y%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D0)
Solving for the second derivative, we have

Now, when

and

, we have