Plzzzzzzzzzz tell how to do the 2nd part in question 27
1 answer:
Hey ,
Here is the answer to ur question...
Given: A triangle in which area =144root3 cm^2....
To find: Perimeter of the triangle...
Solution: As we know area of an equilateral triangle =root3/4 a^2.....
and given area is 144root3
=>Area =144root3
=>root3/4a^2=144root3
=>a^2=144root3*4/root3
=>a^2=144*4
=>a^2=576
=>a=root576
=>a=24
So,now we got each side of the triangle as 24cm.
=>perimeter=side*3=24*3=72cm....
Hope this helps u....
Here is the answer to ur question...
Given: A triangle in which area =144root3 cm^2....
To find: Perimeter of the triangle...
Solution: As we know area of an equilateral triangle =root3/4 a^2.....
and given area is 144root3
=>Area =144root3
=>root3/4a^2=144root3
=>a^2=144root3*4/root3
=>a^2=144*4
=>a^2=576
=>a=root576
=>a=24
So,now we got each side of the triangle as 24cm.
=>perimeter=side*3=24*3=72cm....
Hope this helps u....
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To find the zero you must set each factor equal to zero and solve for for x like so...
Factor (x - 7)
x - 7 = 0
x = 7
Factor (x + 4)
x + 4 = 0
x = -4
Factor (3x - 2)
3x - 2 = 0
3x = 2
x =
All the zeros are:
-4, , 7
Hope this helped!
~Just a girl in love with Shawn Mendes