Plzzzzzzzzzz tell how to do the 2nd part in question 27
1 answer:
Hey ,
Here is the answer to ur question...
Given: A triangle in which area =144root3 cm^2....
To find: Perimeter of the triangle...
Solution: As we know area of an equilateral triangle =root3/4 a^2.....
and given area is 144root3
=>Area =144root3
=>root3/4a^2=144root3
=>a^2=144root3*4/root3
=>a^2=144*4
=>a^2=576
=>a=root576
=>a=24
So,now we got each side of the triangle as 24cm.
=>perimeter=side*3=24*3=72cm....
Hope this helps u....
Here is the answer to ur question...
Given: A triangle in which area =144root3 cm^2....
To find: Perimeter of the triangle...
Solution: As we know area of an equilateral triangle =root3/4 a^2.....
and given area is 144root3
=>Area =144root3
=>root3/4a^2=144root3
=>a^2=144root3*4/root3
=>a^2=144*4
=>a^2=576
=>a=root576
=>a=24
So,now we got each side of the triangle as 24cm.
=>perimeter=side*3=24*3=72cm....
Hope this helps u....
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Answer:
(d)
Step-by-step explanation:
Given
Required
The intercepts
The x intercepts are where the graph crosses x axis.
From the attached plot, they are:
and
These represent the start and end of the ball that is launched.
Hence, (d) is true