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KatRina [158]
3 years ago
14

A dime has a radius of 8.5 millimeters. Find the circumference of a dime to the nearest tenth

Mathematics
1 answer:
g100num [7]3 years ago
3 0
Well C=Dπ so C=17 x 3.14 = 53.38 which is rounded to 53.4
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i have a $500 in my account after 4 years of investing at 2.5% per year, how much money did I start with?
dem82 [27]
You started with $452. Hope I helped and good luck(: 
3 0
3 years ago
The difference of the square of a number and 24 is equal to 5 times that number. Find the negative solution.
vampirchik [111]

Answer:

the "negative solution" is -3

Step-by-step explanation:

Represent the number by n.

Then n^2 - 24 = 5n

We rewrite this in standard quadratic form:

n^2 - 5n - 24 = 0

This factors as follows;  (n + 3)(n - 8) = 0

The roots are n = -3 and n = 8.  Thus, the "negative solution" is -3

8 0
3 years ago
Gina is making bags of trail mix for hiking club. She will use 20 ounces of walnuts, 11.2 ounces of almonds, and 28.3 ounces of
Romashka-Z-Leto [24]

Answer:

there will be 2.38 ounces in one bag of the trail mix

5 0
2 years ago
Read 2 more answers
Simplify (7x−13)−(x+5)
igor_vitrenko [27]
Greetings!

Simplify.
(7x-13)-(x+5)
Distribute the Parenthesis.
7x-13-x-5
Combine Like Terms.
7x-x-13-5
6x-18

Hope this helps.
-Benjamin
5 0
3 years ago
Read 2 more answers
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
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