Step-by-step explanation:
right angled triangle has 3sides with an angle of 90°
quadrilateral triangle has 3sideswith an angle of 60°each side
Answer:
C. 144 square feet
Step-by-step explanation:
step 1
we know that
The perimeter of a square is given by the formula
where
P is the perimeter
a is the length side of the square
we have
substitute in the formula
solve for a
divide both sides by 4
step 2
Find the area
The area of a square is given by the formula
we have
substitute
Answer:
3. 72= (x)+(x+1)+(x+2) where x= the smallest number
72=3x+3
-3 -3
69=3x
/3 /3
x=23
x+1=24
x+2=25
smallest is 23
4. 48= (x)+(x+2)+(x+4)
48= 3x+6
-6 -6
42=3x
/3 /3
x=14
x+2=16
x+4=18
smallest is 14
5. all erasers were the same cost
25= 4x+5 (x= cost of erasers)
-5 -5
20=4x
/4 /4
x=5
each cost $5
6. b= boxes
22= b/2 +7
-7 -7
15=b/2
multiply both sides by 2 to cancel the denominator
30=b
30 boxes originally
7. 40= total
8= left
2= balls given to each
x=number of friends
40= 2x+8
-8 -8
32=2x
/2 /2
x=16
she has 16 friends
8. 12= left
a= total allowance
12= (a/2) +4
-4 -4
8= a/2
multiply both sides by 2 to cancel the denominator
a= $16
she had an allowance of $16
9. 4 (2) = amount that her four children recieved
10=amount she took for herself
x= original
x= 4(2) + 10
x= 8 +10
x=18
she started with 18 candies
10. a= age
244= 400 - 2a
-400 -400
-156= -2a
/-2 /-2
a= 78
they are 78 years old
11. c= comic books
36= c/2 + 16
-16 -16
20=c/2
multiply both sides by 2 to cancel the denominator
c=40
she started with 40 comic books
12. b= students in buses
472= 9b + 4
-4 -4
468=9b
/9 /9
b= 52
52 students went in each bus
13. h= hats
17= h/2 +5
-5 -5
12=h/2
multiply both sides by 2 to cancel the denominator
h=24
she had 24 hats on monday
14. p= pies the club made
60= (p+4)/5
multiply both sides by 5 to cancel the denominator
300=p+4
-4 -4
p= 296
the club made 296 pies
Step-by-step explanation:
Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8
Hope this will help you!
Answer:
Hypothenus = 22
Step-by-step explanation:
From the question given above, we were told that the triangles are congruent (i.e same size). Thus,
AC = EF
BC = DE
To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:
For y:
AC = y + 3
EF = 2y + 1
AC = EF
y + 3 = 2y + 1
Collect like terms
3 – 1 = 2y – y
2 = y
y = 2
For x:
BC = 5x + 7
DE = 6x + 2y
y = 2
DE = 6x + 2(2)
DE = 6x + 4
BC = DE
5x + 7 = 6x + 4
Collect like terms
7 – 4 = 6x – 5x
3 = x
x = 3
Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:
Hypothenus = BC
Hypothenus = 5x + 7
x = 3
Hypothenus = 5x + 7
Hypothenus = 5(3) + 7
Hypothenus = 15 + 7
Hypothenus = 22
OR
Hypothenus = DE
DE = 6x + 2y
y = 2
x = 3
Hypothenus = 6(3) + 2(2)
Hypothenus = 18 + 4
Hypothenus = 22
