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3 years ago

Please help me with this. 10 points! (Math)

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Felt appears to be right triangles

A appears to be an equilateral triangle

Blababa [14]3 years ago

6 0

The answer is B. FELT, a right triangle has at least one angle that is 90 degrees.

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Factorise 4a^2+b^2-4ab-8a+4b+4

Dima020 [189]

Answer:

The factorized form of the given expression is $4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$

Step-by-step explanation:

Given;

4a² + b² - 4ab - 8a + 4b + 4

This expression is factorized as follows;

(4a² - 8a + 4) + (b² - 4ab + 4b)

(4a² - 4a - 4a + 4) + b² - 4b(a - 1)

(4a - 4)(a - 1) + b² - 4b(a - 1)

(4a - 4)(a - 1) - 4b(a - 1) + b²

4(a - 1)(a - 1) - 4b(a - 1) + b²

4(a - 1)² - 4b(a - 1 + b/4)

$4(a- 1)^2 - 4b(a - 1 + \frac{b}{4} )\\\\4 [(a-1)^2 - b(a - 1 + \frac{b}{4})]$

6 0

2 years ago

A. zero B. negative C. positive

Alja [10]

The answer is zero sorry if I am wrong

7 0

2 years ago

Read 2 more answers

Ve a reason why an object with a base toppleasily the one with

zmey [24]

Answer:

i dont understand the questoin plzz write clearly while asking the question plzz

3 0

2 years ago

Write ‒6x^2 + 13x ‒ 6 as the product of two binomials.

VLD [36.1K]

Should be (x-1.5)(x-2/3)

5 0

2 years ago

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

3 years ago