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prohojiy [21]
3 years ago
5

Put the following in order from largest to the smalles 0.2 60% 0.75

Mathematics
2 answers:
maw [93]3 years ago
6 0
So we can first convert the percentages to decimals. This means we would turn 60% into 0.6. So we have 0.2, 0.6, and 0.75. We know that 0.75 is the closest to 1, so it is the largest, 0.6 is the second closest, so it is the second largest, and 0.2 is the farthest, so it is the smallest. Therefore the order is:

1st: 0.75
2nd: 60%
3rd: 0.2.

Hope this helps. :D Feel free to ask more questions or ask about my explanation.
PilotLPTM [1.2K]3 years ago
3 0
First ,0.75


Second, 60%



Third , 0.2
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Y_Kistochka [10]

Given:

Sharon uses 6.3 pints of blue paint and white paint to paint her bedroom walls.

\dfrac{4}{5}th of this amount is blue paint and the rest is white paint.

To find:

The pints of white paint did she use to paint her bedroom walls.

Solution:

We have,

Total paint used = 6.3 pints

Blue paint = \dfrac{4}{5}th of total paint used

                 = \dfrac{4}{5}\times 6.3

                 = 5.04

White paint = Total paint used - Blue paint

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Therefore, Sharon uses 1.26 pints of white paint to paint her bedroom walls.

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3 years ago
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

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Step-by-step explanation:

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P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

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Answer:

Step-by-step explanation:

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