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3 years ago

12

eton's baby sister took a nap for 2 hours and 22 minutes yesterday and 1 hour and 35 minutes today.how many minutes did she slee

p yesterday than today

2 answers:

Ksenya-84 [330]3 years ago

6 0

2:22

-1:35

______

47 minutes

7nadin3 [17]3 years ago

6 0

The answer to your question is 47

120min + 22min = 142

142 + 95 = 47

47 minutes Total

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Let T:R²->R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)

zavuch27 [327]

Answer:

(-4,-1)

Step-by-step explanation:

We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

4 0

2 years ago

The closer the slope value is to zero, the steeper the line. yes or no

Harrizon [31]

No, that is not true. Use the website desmos.com to try it out yourself. Graph equations like y=1x, y=1/2x, and y=1/4x to try. Then, you will see that as the number gets bigger, the line gets steeper (it gets higher..like a hill..rising..)

7 0

3 years ago

Once again co sines . Please help me and include explanation with a clear answer

vladimir1956 [14]

Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)

a = 17, b = 8, c = 16

8^2 = 17^2 + 16^2 - 2*17*16* cos(B)

64 = 289 + 256 - 544 * cos(B)

544*cos(B) = 289 + 256 - 64

544 * cos(B) = 481

cos (B) = 481/544

B = arccos(481/544)

B = 27.8 degrees

8 0

3 years ago

Solve the equation<br>2/3 h - 1/3 h + 11 = 8<br><br>h = ?

Deffense [45]

Answer:

$2 \div 3h - 1 \div 3 h+ 11 = 8 \\ 2 - 1 \div 3h = - 3 \\ 1 \div 3h = - 3 \\ - 9h = 1 \\ h = - 1 \div 9$

-1/9 is the answer

8 0

2 years ago

Which equation represents the line that passes through (-6, 7) and (-3, 6)?

Degger [83]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

$(x_ {1}, y_ {1}): (- 6,7)\\(x_ {2}, y_ {2}): (- 3,6)$

We find the slope of the line:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {6-7} {- 3 - (- 6)} = \frac {-1} {-3 + 6} = \frac {-1} {3} = -\frac {1} {3}$

Thus, the equation of the line is of the form:

$y = - \frac {1} {3} x + b$

We substitute one of the points and find b:

$6 = - \frac {1} {3} (- 3) + b\\6 = 1 + b\\b = 5$

Finally, the equation is:

$y = - \frac {1} {3} x + 5$

Answer:

$y = - \frac {1} {3} x + 5$

8 0

3 years ago