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Alchen [17]
3 years ago
6

Can someone help me? It's urgent and thank you!

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0

Answer:

35 or A

Step-by-step explanation:

This is a combinations problem because the order doesn't matter (it's a council, not like president and v.p.). C(7, 3) is 7!/(4!*3!) = 7*6*5/3*2 = 35. Hope this helps! :)

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A manager forecasts that 150 guests will be served tomorrow. The manager knows that one server can provide high quality service
iVinArrow [24]

Answer:

5 servers and 3 cooks(since a person doesn't exist in fraction)

Step-by-step explanation:

From the question provided above, the manager(who is obviously organizing some kind of party or get-togethers) is expecting a hindered and fifty guests in total .

And it also says that if a server can handle 30 guests and 150,how many of them are need?

Let X be number of servers needed:

X= 150/30 = 5 servers

AND

If a single cook can prepare meals for 60 guests,the number of cooks required to cover for 150 guest will be:

X= 150/60 = 2.5,but since a fraction of a human doesn't exist, we have to say that the manager needs 3 cooks(2 of them will handle a total of 120 guests and the other cook handles the 30 guests)

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