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Semenov [28]
3 years ago
11

Help with math please

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
6 0

Answer:

C=both a and b

Step-by-step explanation:

Karo-lina-s [1.5K]3 years ago
4 0

Answer:

C. both A and B...............

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Answer:

The answer is 1251, the remainder is 3.

Step-by-step explanation:

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4x-4/5=2/5 solve the equation
cestrela7 [59]

Answer:

x=0.3

Step-by-step explanation:

4x-4/5=2/5

4x=4/5+2/5=6/5

x=6/20=3/10=0.3

4 0
3 years ago
Read 2 more answers
Convert 6 and 3/5 to an improper fraction.
VikaD [51]

Answer: 33/5

Step-by-step explanation:

6 x 5 = 30

30 + 3 = 33

7 0
4 years ago
Read 2 more answers
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
Sophia puts $250 in the bank with a 2.5% annual interest rate compounded monthly. If Sophia does not touch his money, how much m
Fittoniya [83]

Answer:

<h3> D) $276.26</h3>

Step-by-step explanation:

Deposited amount initially (P) = $250.

Rate of interest(r) = 2.5% compounded monthly = 0.025

Number of years (t) = 4.

Number of months in an year (n) = 12.

Formula for compound interest:

A=P(1+\frac{r}{n})^{nt}.

Plugging values in formula, we get

A= 250(1+\frac{0.025}{12})^{12\times 4}

A= 250(1.00208)^{48}

A= 250\times \:1.10506

A=276.26.

<h3>Therefore, correct option is  D) $276.26.</h3>
7 0
3 years ago
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