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Rama09 [41]
3 years ago
7

Use parallel lines cut by a transversal properties to solve for X

Mathematics
1 answer:
inysia [295]3 years ago
6 0

Answer:

uh

Step-by-step explanation:

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Factor completely.
Zolol [24]

Answer:

B) 6(x-5) (x+5)

Step-by-step explanation:

Common factor.

6 ( ^2 − 25)

Use the sum-product pattern.

6 ( ^2+5−5−25).

Common factor from the two pairs.

6((+5)−5(+5)).

Rewrite in factored form.

6 ( − 5 ) ( + 5).

4 0
3 years ago
Can someone help me with this math homework please!
Maksim231197 [3]

Answer:

2nd option

{(-8, -2), (-4, 1), (0, -2), (2, 3), (4, -4)}

Step-by-step explanation:

For a function to exist, every value of input must have exactly one value of output.

The rest of the relations(1, 3, and 4) have 2 outputs for 1 input so they dont make a function.

3 0
3 years ago
Read 2 more answers
CAN SOMEONE PLEASE
pishuonlain [190]

Answer: The graph is shown below

The solution to the system is (x,y) = (2,3)

=============================================================

Explanation:

To graph y = \frac{5}{2}x-2, we need two points. Generating any (x,y) point involves picking a random x value to find its paired y value. For instance, if you plugged in x = 0, you should get to y = -2 which is the y intercept. Then trying something like x = 2 will lead to y = 3. This line goes through (0,-2) and (2,3). This line is shown in red below.

The blue line is horizontal and goes through 3 on the y axis. Every point on this horizontal line has the same y coordinate of 3. The x value doesn't matter, so it's not part of the equation y = 3.

The intersection of the red and blue line is the solution to the system. That intersection occurs at (x,y) = (2,3). This means x = 2 and y = 3 pair up together to make both original equations true.

Since this system has at least one solution, we consider it a consistent system.

5 0
3 years ago
Simulate the rolling of two dice 10,000 times. (b) Identify which rolls of the dice are in the event A, the dice add up to a per
dexar [7]

Answer:

Answer explained below

Step-by-step explanation:

(a)

Simulate the rolling of two dice 10,000 times D1 and D2 are the 10,000 results of roll of dice 1 and dice 2.

D1 = sample(c(1:6), 10000, replace = TRUE)

D2 = sample(c(1:6), 10000, replace = TRUE)

Sum = D1 + D2

(b)

The event A, the dice add up to a perfect square (4 or 9).

A = Sum[Sum == 4 | Sum ==9]

Proportion of A, P(A) = 0.189

length(A) / length(Sum)

(c)

The event B, the dice add up to an even number.

B = Sum[Sum %% 2 == 0]

Proportion of B, P(B) = 0.5049

length(B) / length(Sum)

(d)

The  rolls are in A ∩ B (common to both A and B)

> intersect(A,B)

[1] 4

The proportion that are in A ∩ B is 0.0792

length(Sum[Sum == 4]) / length(Sum)

P(A) * P(B) = 0.189 * 0.5049 = 0.0954

The proportion in A multiplied by the proportion that are in B is not equal to P(A ∩ B)

(e)

Of the rolls in which B occurs, the proportion of those rolls are also in A is 0.4190476

length(Sum[Sum == 4]) / length(A)

This proportion is greater than the P(A) calculated in part (b).

4 0
3 years ago
What is the surface area of a sphere with a radius of 6 units?
finlep [7]

Answer:

452.39

Step-by-step explanation:

i think

7 0
3 years ago
Read 2 more answers
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