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AleksandrR [38]
3 years ago
8

Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. (assume that

n begins with 1.) {2, 9, 16, 23, 30, . . . }
Mathematics
1 answer:
Alex73 [517]3 years ago
7 0
This is an arithmetic sequence with first term 2 and common difference 7. The general term a[n] can be written as
  a[n] = 2 +7(n -1)
or
  a[n] = 7n -5
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What is 25 x 10^6 I need to know fast
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25000000

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First you get rid of your exponents so 10^6 = 1000000 then multiply 25 and get 25000000

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In the image below, ∠B≅∠E. What similarity criterion proves that △ABC~△FED?
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When dividing polynomials using factorization, cancelling identical factors in the denominator and the numerator will give the _
sladkih [1.3K]

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a. remainder

3 0
3 years ago
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Which is the cheapest per ounce: a 2-L bottle (67.6 oz.) of root beer at $1.49, a six-pack of 20-oz. bottles at $2.49, or a twel
KatRina [158]
Divide 1.49$ by 67.6oz=.020414201
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8 0
3 years ago
Getting enough sleep. 400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Co
coldgirl [10]

Answer:

Yes, Hypothesis test represents a statistically significant difference from 50% .

Step-by-step explanation:

We are given that 400 students were randomly sampled from a large university, and 289 said they did not get enough sleep.

Let Null Hypothesis, H_0 : p = 0.50 {means from the students sampled from the university, proportion of them who did not get enough sleep is 50%}

Alternate Hypothesis, H_1 : p \neq 0.50 {means from the students sampled from the university, proportion of them who did not get enough sleep is different from 50%}

The test statistics we will use here is;

        T.S. = \frac{\hat p - p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } ~ N(0,1)

where, \hat p = sample proportion = 289/400 = 0.7225

            n = sample of students = 400

So, test statistics = \frac{0.7225 - 0.50}{\sqrt{\frac{0.7225(1-0.7225)}{400} } } = 3.143

<em>Now, at 1% level of significance, z table gives critical value of 2.5758. Since our test statistics is more than the critical value which means test statistics will lie in the rejection region, so we have sufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that from the students sampled from the university, proportion of them who did not get enough sleep is different from 50%.

7 0
3 years ago
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