<h3>
Answer: y = 12/(x^2)</h3>
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Explanation:
"y varies inversely as x^2" means y = k/(x^2) for some constant k.
Plug in (x,y) = (2,3) and solve for k
y = k/(x^2)
3 = k/(2^2)
3 = k/4
3*4 = k
12 = k
k = 12
The original equation updates to y = 12/(x^2)
As a check, plugging in x = 2 should lead to y = 3
y = 12/(x^2)
y = 12/(2^2)
y = 12/4
y = 3 ... we get the proper y value, so the answer is confirmed.
Answer:
2
Step-by-step explanation:
Answer:
In this problem, I can not tell what is V, so I will answer it in a general way.
A polynomial is something of the form:
a*x^5 + b*x^4 + c*x^3 + d*x^2 + e*x + f
a, b, c, d, e, and f are real numbers and constant.
Where the degree of the polynomial is equal to the greatest power (in this case 5).
You write:
4x^2 + 3Vx + 5
Now, if V is a real number, then we have that this is a polynomial of degree 2.
Because we can write this as:
4*x^2 + (3V)*x + 5
So the answer is true.
Now, if V is a variable or an operation, the answer will be false.
Answer:
2 x 10 to the -6th power is .000002.
