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guajiro [1.7K]
3 years ago
15

Are penn foster highschool proctored exams optional?​

SAT
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

Starting in 2014, Penn Foster began introducing online proctoring as an additional option to a face-to-face proctor. Since then, thousands of remote proctored exams have been taken on Penn Foster’s systems, with less than 1% of proctored events flagged for infractions. What does this mean? It means that within this exam environment, students are unlikely to cheat. To simulate a traditional test-taking environment, the student is given strict guidelines regarding what they can and cannot do, including rules for what they are allowed to bring into the room with them, and when they are allowed to leave. The student is recorded via webcam while the testing system controls what the student sees on their screen. For additional identity verification, students are asked to present their license or ID to the webcam. The remote proctoring platform audits the recordings after the fact, and contacts Penn Foster with any reports of infractions.

For students who are unable to take remote proctoring, they must use paper proctored exams. In this case, the student finds someone who meets the requirements to proctor the exam, and Penn Foster verifies the individual. Penn Foster continues to work to switch over all exams to the remote proctor option, via an ongoing programmatic roll-out

Explanation:

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Based on the calculations, we have the following:

  1. The area of the sheet of paper is 96 square inches.
  2. The combined area of the triangle cutouts is equal to 36 square inches.
  3. The area of the parallelogram is equal to 60 square inches.
  4. The altitude of the parallelogram is equal to 6.51 square inches.

<u>Given the following data:</u>

  • Dimension of paper = 12-inch by 8-inch.

<h3>How to calculate the paper's area.</h3>

Mathematically, the area of the paper is given by this formula:

Area = length \times breadth\\\\Area = 12 \times 8

Area = 96 square inches.

<u>For the four (4) right triangles:</u>

  • Dimension 1 = 2 inches by 9 inches.
  • Dimension 2 = 3 inches by 6 inches.

Therefore, the combined area of the triangle cutouts is given by:

A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2

<h3>The area of the parallelogram.</h3>

This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:

P = A_p -A_2\\\\P=96-36

P = 60 square inches.

<h3>The altitude of the parallelogram.</h3>

P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}

Altitude = 6.51 square inches.

Read more on parallelogram here: brainly.com/question/4459854

<u>Complete Question:</u>

A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.

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How many electrons pass through a 20-ohms resistor in 10 min if there is a potential drop of 30 volts across it?
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The number of electrons passes through 20 ohms resistor in 10  minutes is 5.625e+21.

<h3>What is a resistor?</h3>

In an electronic circuit, a resistor is an electrical component that limits or regulates the flow of electrical current.

Given, the resistance is 20 ohms.

The potential difference is 30 volts

Time is 10 minute

By the formula of current

\rm I = \dfrac{30}{20} = 1.5 \;C/s

The charge flowing through the resistor is 1.5 C/s

1 electron charge is 1.6e+19

Now, the number of electrons passing through a 20 ohms resistor is

\dfrac{1.5}{1.6e+ ^2^1} = 0.9375e+^1^9

In 10 minutes

0.9375e+^1^9 \times 60 \times 10 = 5.625e+^2^1

Thus, the number of electrons passes through 20 ohms resistor in 10  minutes is 5.625e+21.

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