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aleksandr82 [10.1K]
3 years ago
11

Helpppp please I'm really stuck on this question

Physics
2 answers:
finlep [7]3 years ago
8 0
Your answer would be C. We just went over this in my class
amm18123 years ago
6 0
Is this a test? If it is, i’m not allowed to help as i would be seen as a bad person! I hope you pass, god bless.
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What is the speed of sound in dry air if the temperature is 46°C?
maria [59]
The speed of sound at 46 C is 800.91 mph
7 0
3 years ago
A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used
zloy xaker [14]

Answer:

The compression is \sqrt{2} \  d.

Explanation:

A Hooke's law spring compressed has a potential energy

E_{potential} = \frac{1}{2} k (\Delta x)^2

where k is the spring constant and \Delta x the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

E_{kinetic} = \frac{1}{2} m v^2.

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity v_1. Knowing that the energy is constant.

\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2

But, in the left side we can use the previous equation to obtain:

2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2

D^2 =  \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}

D^2 =  2 \  d^2

D =  \sqrt{2 \  d^2}

D =  \sqrt{2} \  d

And this is the compression we are looking for

3 0
4 years ago
Read 2 more answers
Help omg
Drupady [299]
52.4934 meters per second
3 0
3 years ago
Read 2 more answers
A playground ride requires 21 seconds to make one complete revolution
luda_lava [24]

The angular speed of the playground ride is determined as 0.3 rad/s.

<h3>What is angular speed?</h3>

Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.

<h3>Angular speed of the ride</h3>

The angular speed of the ride if the ride makes one complete revolution is calculated as follows;

ω = θ/t

ω = 2π/t

where;

  • ω is angular speed of the ride
  • t is time of motion of the ride

one complete revolution = 2π radians

ω = 2π/21

ω = 0.3 rad/s

Thus, the angular speed of the playground ride is determined as 0.3 rad/s.

Learn more about angular speed here: brainly.com/question/24158647

#SPJ1

The complete question is below;

A playground ride requires 21 seconds to make one complete revolution, what is angular speed of the ride in radian per second.

3 0
2 years ago
Which words help you to determine the meaning of the word decelerate in paragraph 3
Novay_Z [31]

Answer:

the words

Explanation:

4 0
3 years ago
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