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vladimir2022 [97]
3 years ago
14

Please I need help with this question

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0
This is a function because each input has exactly one output ❤️
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A new car is purchased for 24800 dollars. The value for f the car depreciates at 12% per year. What will the value of the car be
laila [671]

Answer:

$4706.81

Step-by-step explanation:

The value each year is multiplied by 100% -12% = 88% = 0.88. After 13 years, the value is 0.88^13 ≈ 0.1897906 times what it was originally: ≈ 4,706.81 dollars.

6 0
4 years ago
How much times dose 9 go into 125???
lesya692 [45]
125:9=\frac{125}{9}=\frac{90+36-1}{9}=\frac{90}{9}+\frac{36}{9}-\frac{1}{9}=10+4-\frac{1}{9}=14-\frac{1}{9}\\\\=13\frac{8}{9}\approx14\\\\Answer:\ 9\ go\ into\ 125:\ 13\frac{8}{9}\ times,\ approximate\ to\ 14
7 0
3 years ago
Alberto recorded the heights of the basketball team members.
kramer
C. The Venn Diagram because Alberto is trying to recorded the heights of the basketball players not compare the heights.
3 0
4 years ago
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that
Cloud [144]

ANSWER

Find out the  how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.

To proof

As given

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.

the total part of the alloy are 18.

assuming one part be x.

thus

nickel part = 2x

zinc part = 7x

copper part = 9x

alloy that contains 4.9 lb of zinc.

than the equation becomes

7x = 4.9

x = \frac{4.9}{7}

x = 0.7

Therefore

nickel part = 2x

                  = 2× 0.7

                  = 1.4 lb

1.4 lb of nickel have to be used to create alloy that contains 4.9 lb of zinc.

Hence proved

4 0
3 years ago
Read 2 more answers
Dominic spent 2 3/4 hours on his art project. Rachel worked 1 1/3 times as long on her rt project as Dominic worked. For how man
Travka [436]
Dominic = 2 3/4

Rachel = 1 1/3 x 2 3/4 = 11/3 = 3 2/3 hour

Answer: 3 2/3 hour

3 0
3 years ago
Read 2 more answers
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