First, we need to work out the total number of students who were being surveyed.
We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population
That means total number of students being surveyed is 13+13=26 students
Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13
The probability distribution is shown in the table below. Let

be the number of pets and

is the probability of owning the number of pets
Answer:
Step-by-step explanation:
line graph- the decrease of attendance
bar graph-the number of students who participate in different sports
line plot-the list of heights of a group of 80 adults
steam and leaf plot- the number of dogs for students
The equation you can use is x + 3x = 428 with x as the number of cheeseburgers and 3x the number of hamburgers
you solve for x and get 4x= 428 and x=107
so 321 hamburgers were sold that day.
=theta/360°×2pi ×r
theta=180-60=120°
r=24÷2=12
120/360 × 2 × 22/7 × 12=
1/3 × 2 × 22/7 × 12=
176/7=
25.14
-78
Step-by-step explanation:
(7-8)(78)
(-1)(78)=-78