Question

Write an equation for the line parallel to the given line that contains C C(2,6); y= -4x + 7

Answer 1

Answer:

$y=-4x+14$

Step-by-step explanation:

step 1

Find the slope of the given line

we have

$y=-4x+7$

This is the equation of the given line in slope intercept form

The slope is $m=-4$

step 2

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are the same

therefore

The slope of the line parallel to to the given line is $m=-4$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=-4$

$C\ (2,6)$

substitute

$y-6=-4(x-2)$

step 4

Convert to slope intercept form

$y-6=-4(x-2)$

isolate the variable y

$y-6=-4x+8$

$y=-4x+8+6$

$y=-4x+14$