5.
f(K) = D^3 => f(25) = 125 => 25 * t = 125 ( because K is directly proportional with D^3 )=> t = 125 / 25 => t = 5 => f(25) = 25 * 5 => K * 5 = D^3 ;
6.
f(L) = F^3 => f(2) =3^3 =>f(2) = 27 => 2 / t =27 => t = 2 / 27 => t = 0.074 => f(2) = 2 / 0.074 => K / 0.074 = F^3 ;
Let

be the length of the rectangle and

be the width. In the problem it is given that

. It is also given that the area

. Substituting in the length in terms of width, we have

. Using the zero product property,

. Solving these we get the width

. However, it doesn't make sense for the width to be negative, so the width must be

. From that we can tell the length

.
12 hours? If I'm wrong, sorry about that
Answer:
The period of the
function is
. Then three times this period is
.
Step-by-step explanation:
Using Mathematica you can use the command Plot as follows:
```
Plot[Sin[x], {x,0,6Pi}]
```
The output is the graph shown below.
Answer: (positive) 12
Step-by-step explanation: