3 years ago

Whut is the soluton of when multiplying by 3

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

The answer of this is 3,6,9,12,15,18,21,24,27,30,33,36,39,...

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madam [21]

parallel when a=2

perpendicular when a=-1/2

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3 years ago

800,000,000,000 + 20,000,000,000 + 3,000,000,000 + 50,000,000 + 4,000,000 + 600,000 + 50,000 + 8,000 + 700 + 80 + 6

WITCHER [35]

823054658786 is the answer to your question

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3 years ago

Abigail withdrew $15 from checking account. Write an integer to represent the situation.

aleksandrvk [35]

Answer:

-5

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2 years ago

A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between

sattari [20]

Answer:

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) 0.09

Step-by-step explanation:

We are given the following in the question:

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)$

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

$B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)$

b) rate of increase after one day.

We put t = 1

$B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09$

The rate of increase after 1 day is 0.09

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2 years ago

How many yards are in 1 mile 600 ft

crimeas [40]

A mile is a unit of length most commonly equivalent to 5280 feet (1760 yards, or about 1609 metres).

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3 years ago

Read 2 more answers