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3 years ago

How do you solve 4b^2+8b+7=4 using the quadratic formula

Mathematics

2 answers:

Alchen [17]3 years ago

8 0

B= { (-8) ± Sqrt(8^2)-4(4x(3) ) } / 2(4)
b={ (-8±) (Sqrt(16) ) } / 8
b=(-8+4)/8 and b=(-8-4)/8
b= -4/8 and b=-12/8
b=-1/2 and b=-3/2
b={-1/2, -3/2} is the solution.
Click image for formula.
Sqrt means Square Root.

lina2011 [118]3 years ago

4 0

$
4b^2+8b+7=4\\
4b^2+8b+3=0\\\\
x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\
x=\dfrac{-8\pm\sqrt{8^2-4\cdot4\cdot3}}{2\cdot4}\\
x=\dfrac{-8\pm\sqrt{64-48}}{8}\\
x=\dfrac{-8\pm\sqrt{16}}{8}\\
x=\dfrac{-8\pm4}{8}\\
x=\dfrac{-2\pm1}{2}\\
x=\dfrac{-1}{2 }\vee x=\dfrac{-3}{2}\\
x=-\dfrac{1}{2 }\vee x=-\dfrac{3}{2}$

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Step-by-step explanation:

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$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

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Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

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Step-by-step explanation:

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