If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.
We are required to find the speed of slower car and faster car.
let the speed of slower car be x mph.
In this way the speed of faster car be (x+20) mph.
Speed=Distance/ time
We have to first take slower car.
x=165/Time
Time=165/x-----------1
Now by taking faster car.
x+20=225/time
Time=225/(x+20)-------2
From equation 1 an equation 2.
165/x=225/(x+20)
225x=165x+3300
225x-165x=3300
60x=3300
x=55 mph
Faster car=55+20
=75 mph.
Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.
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Answer:
The equation is
n = PRT/100
The value of p
p = $1250
Step-by-step explanation:
Simple interest= n
Rate of interest = r
Number of years = t
Then principal amount= p
This p can be said to be the constant of the equation because it's value never changes
n = $225
r = 4.5%
t = 4 years
The interest varies jointly with the rate, the time and the principal amount.
The equation for the relationship
n > prt
But r is in percentage
n = PRT/100
For the value of p
p =(225*100)/(4.5 *4)
p= 22500/18
p= 1250
p = $1250
Answer:
The probability of getting someone in the 18-21 age bracket or someone who agreed to respond
Step-by-step explanation:
The counts are as follows
Age Group No of people contacted No of refusals Total
18-21 88 8 96
22-29 240 42 282
Total 328 50 378
The probability of getting some one in the age bracket of 18-21 or some one who refused to respond is
You can break the equation into two groups:
6a² + 5a - 6
(9a - 6) + (6a² - 4a)
Simplify:
(9a - 6)
3(9a - 6)
(3a - 2)
--------------------------
(6a² - 4a)
2a(6a² - 4a)
(3a - 2)
--------------------------
(3a - 2)(2a+3)
You can't simplify any further, so that will be your answer.
Answer:
(2a + 3)(3a - 2)
Answer:
The 4th Option
Step-by-step explanation:
For a graph to be a function, it must not be broken up at any point (as in Option 3) and there can be no points that overlap each other vertically (as in Options 1 and 2). So, the only option that is continuous and with no overlapping points is Option 4.