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agasfer [191]
3 years ago
10

Vanya collects vintage albums. Each storage unit holds 16 albums. She gave 3 albums to her cousin as a graduation present. Which

function shows the relationship between y, the total number of albums she has remaining, and x, the number of storage units Vanya owns?
a.y = 16x
B.y = 16x + 3
C.y = 13x
D.y = 16x – 3
Mathematics
1 answer:
damaskus [11]3 years ago
7 0

Answer:

d

Step-by-step explanation:

vintage gave her cousin 3 albums when she had 16

so y=16x-3.

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Jesse walked 3/4 of a mile last weekend. This weekend he wakes 1/2 as far. How far did Jesse wall this weekend ?
Anna35 [415]

3/8 is the answer

3/4 divided by 1/2= 3/8

Hope this helps!

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What is 1/2 • 2 - 1 =
ozzi

Answer:

0

Step-by-step explanation:

1/2 * 2 is 1. 1 - 1 is 0

Have a great day/night!

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Is (-3,4) a solution of the inequality y> - 2x – 3?
jeyben [28]

Answer:

  (-3, 4) is a solution

Step-by-step explanation:

The point (-3, 4) is inside the shaded area of the graph, so is a solution.

You can check in the inequality

  y > -2x -3

  4 > -2(-3) -3 . . . . substitute for x and y

  4 > 3 . . . . . . . true; the given point is a solution

8 0
3 years ago
Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
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IceJOKER [234]

Answer:

The answer is 45

Step-by-step explanation:

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