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kondor19780726 [428]
4 years ago
6

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
aksik [14]4 years ago
5 0

Answer:

x > 2 = four times a number is more than four

arrowRight

x > 1 =

x < 1 =

x < 4 = four times a number is less than 16 arrowRight

x > 2 = four times a number is less than four

arrowRight

x > 4 = four times a number is more than 16

arrowRight

Step-by-step explanation:

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Answer: the Y-axis

Step-by-step explanation:

y is swapped To negative

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3 years ago
HELP I WILL MARK YOU AS A BRAINLIEST I KNOW IM SO DUMB!!
monitta

Answer:

6.15.

Step-by-step explanation:

3.75 + 2 2/5

= 3.75 + 2.40

= 6.15.

4 0
4 years ago
Read 2 more answers
What is the area of a circle whose diameter is 32 inches? Use pi = 3.14 in your calculations. Show your work.
Mrac [35]

Answer:

Area=  50.24 inches square

Step-by-step explanation:

Area of a circle = π r²            diameter= 2*radius

Area= 3.14*(16) ²

Area=  50.24 inches square

6 0
3 years ago
I need help again...help??
Tasya [4]

Answer:

x ≥14

Closed circle at 14 line to the right

x≤3

closed circle at 3  line to the left

Step-by-step explanation:

(x-4)/5 ≥2

Multiply by 5

(x-4 )/5 *5 ≥2 *5

x-4 ≥10

Add 4 to each side

x-4+4≥10+4

x ≥14

Closed circle at 14 line to the right

3x-4 ≤5

Add 4 to each side

3x-4 +4≤5+4

3x  ≤9

Divide by 3

3x/3  ≤9/3

x≤3

closed circle at 3  line to the left

5 0
3 years ago
Consider the following function.f(x) = 16 − x2/3Find f(−64) and f(64).
malfutka [58]

Answer: f(-64)=0

f64)=0

Step-by-step explanation:

The given function : f(x)=16-x^{2/3}

When we substitute x= -64, we get

f(x)=16-(-64)^{2/3}

Since , 64=4\times4\times4=4^3

So, -64=-4\times-4\times-4=-4^3

That means  f(-64)=16-(-64)^{2/3}=16-(-4^3)^{2/3}

=16-(-4)^2=16-(-4\times-4)=16-16=0

i.e. f(-64)=0

Similarly, When we substitute x= 64, we get

f(x)=16-(64)^{2/3}

Since , 64=4\times4\times4=4^3

That means  f(64)=16-(64)^{2/3}=16-(4^3)^{2/3}

=16-(4)^2=16-16=0

i.e. f64)=0

3 0
4 years ago
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