First find the length of the diagonal of a square of side 4 inches:
d^2 = 4^2 + 4^2 = 2*4^2 = 32. Then the diagonal of the cube has length
sqrt( 32 + 4^2) = sqrt(32+16) = sqrt(48) = 4sqrt(3).
Answer:
(10⁰x 10¹ x 1¹⁰)< (10⁰ + 10¹x 1¹⁰)<(10⁰ + 10¹ + 1¹⁰)< (10 x 10¹)
Step-by-step explanation:
increasing order-
(10⁰x 10¹ x 1¹⁰)
(10⁰ + 10¹x 1¹⁰)
(10⁰ + 10¹ + 1¹⁰)
(10 x 10¹)
Answer:
9
Step-by-step explanation:
substituting 2 for the x
y = 2(2) + 5
y = 4 + 5
y = 9
