
To solve for n, we have to isolate n. To do so, we move all the terms that are not n to one side of the equation, and leave n on the other side.

Equation: n + 5/16 = -1
Subtract 5/16 on both sides to bring it to the right side of the equation.


 
        
             
        
        
        
Answer:
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Answer:
Therefore the required polynomial is 
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
       =a(x+4)(x-4i)(x+4i)
       =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]
       =a(x+4)(x²-16i²)
       =a(x+4)(x²+16)      [∵i² = -1]
       =a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

       =0.83
Therefore the required polynomial is 
M(x)=0.83(x³+4x²+16x+64)
 
 
        
             
        
        
        
Answer:
See below.
Step-by-step explanation:
1.) False - It contains 6 sig figs, not 2.
2.) False - It goes up to 2 decimal places, not 3.
3.) True
4.) False - It goes up to 1 sig fig, not 4.