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puteri [66]
3 years ago
13

In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear pow

er plant, it is found that 63 of 100 urban residents favor the construction while only 59 of 125 suburban residents are in favor. We wish to know if there a significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant. Do the step by step procedure on hypothesis test of two proportions, use 0.05 level.
Mathematics
1 answer:
leva [86]3 years ago
8 0

Answer:

The test statistic z = z = 2.368 >1.97 (at 5% level of significance)

we rejected null hypothesis at 5% level of significance

There is  significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

Step-by-step explanation:

Given data In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant, it is found that 63 of 100 urban residents

The first sample proportion  p₁ = \frac{63}{100} =0.63

The construction of  59 of 125 suburban residents are in favor

The second  sample proportion p_{2} = \frac{59}{125}  = 0.472

Given the sample sizes are n₁ = 100 and n₂ =125

<u>Null hypothesis(H₀):</u>-there is no significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

<u>Alternative hypothesis: H₁</u>

There is  significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

<u>Level of significance</u>:-

∝ =0.05

Tabulated value z=1.96

<u>Test statistic</u>

<u></u>z = \frac{p_{1}-p_{2}  }{\sqrt{pq(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }<u></u>

where p = \frac{n_{1}p_{1} +n_{2}p_{2}  }{n_{1} +n_{2} }         q = 1- p

Substitute all values in above equation

p = \frac{100X0.63+0.472X125}{100+125} = 0.542

q = 1-p = 1 - 0.542 = 0.458

The test statistic

z = \frac{0.63-0.472}{\sqrt{0.542X0.458}(\frac{1}{100}+\frac{1}{125}   )}

on simplification , we get

z = 2.368 >1.97 (at 5% level of significance)

we rejected null hypothesis at 5% level of significance

<u>Conclusion</u>:-

There is  significant difference between the proportions of urban and suburban residents who favor construction of the nuclear plant.

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