Using rectangles of unit width on the interval [3,5], arrange the curves in ascending order of the estimated areas under them. (
Screenshot attached)
1 answer:
The areas can be estimated by adding the function values at the midpoints of the intervals 3–4 and 4–5. Those midpoints are x = 3.5 and x = 4.5. Hence we can approximate the area by adding f(3.5) and f(4.5). That is what is done in the attachments.
Top to bottom, the functions have approximate areas on the interval of ...
... 80, 77.5, 13.4, 50.5, 37.6, 58.325
Of course, the same graphing calculator can do numerical integration and give you the "exact" area (to 10 significant figures or better). The problem statement asks for this approximation, which is actually good enough for the purpose of ordering the values.
See the first attachment for results. See the other two attachments for area estimates and curve definitions (color key).
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Answer:
15 feet
Step-by-step explanation:
This problem involves using the Pythagorean theorem, since the figure made with the ladder, building, and ground would make a right triangle. You are given the values 17ft and 8ft, which is enough to plug into the Pythagorean theorem.
The ladder, 17ft, would be the longest side (hypotenuse). The 8ft building would be one of the legs of the right triangle.
1. Plug your given values correctly into the Pythagorean Theorem.
2. Now solve for b, which is your unknown distance (the distance the bottom of the ladder is from the bottom of the building).
--> Square 8 and 17
--> Subtract 64 from both sides
--> Square root both sides to get b by itself
b = 15
3. The distance is 15 feet
*Note: to make solving this problem easier, try drawing out the given situation, namely the building and the ladder
Given:
side length = 6 ft
To find:
The area of the figure
Solution:
Area of the square = side × side
= 6 × 6
Area of the square = 36 ft²
Diameter of the semi-circle = 6 ft
Radius of the semi-circle = 6 ÷ 2 = 3 ft
Area of the semi-circle =
Area of the semi-circle = 14.13 ft²
Area of the figure = Area of the square - Area of the semi-circle
= 36 ft² - 14.13 ft²
= 21.87 ft²
Area of the figure = 21.9 ft²
The area of the figure is 21.9 ft².
Given length of a lap = 5/8 mile.
Number of laps Carin ran = 3 1/2 laps.
3 1/2 can be read as 3 and a half. In improper fractions, it can be written as
(3*2+1)/2 = 7/2 laps.
In order to find the total distance covered in 3 1/2 or 7/2 laps, we need to multiply length of a lap by total number of laps ran.
Therefore, total distance covered = 7/2 × 5/8.
=
Multiplying across, we get
=
=
Let us convert 35/16 into mixed fractions.
On dividing 35 by 16, we get 2 quotient and 3 remainder.
So, the mixed fraction would be 2 3/16.
Therefore, she ran 2 3/16 miles in 3 1/2 laps.