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3 years ago

Find the value of X (5x+4)°+(8x-71)°

Mathematics

1 answer:

NikAS [45]3 years ago

5 0

Answer:

x = -4/5

Step-by-step explanation:

Solve for x:

(5 x + 4) (8 x - 71) = 0

Split into two equations:

5 x + 4 = 0 or 8 x - 71 = 0

Subtract 4 from both sides:

5 x = -4 or 8 x - 71 = 0

Divide both sides by 5:

x = -4/5 or 8 x - 71 = 0

Add 71 to both sides:

x = -4/5 or 8 x = 71

Divide both sides by 8:

Answer: x = -4/5 or x = 71/8

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Answer:

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3 years ago

given line passes through the points (-4, -3) and( 4, 1) what is the equation in point slope form of the line that's perpendicul

Diano4ka-milaya [45]

Answer:

y= -2x-5

Step-by-step explanation:

First find the gradient of the first line

$m = \frac{y2 - y1}{x2 - x1}$

$\frac{1 - - 3}{4 - - 4}$

$\frac{4}{8}$

m=1/2

From this we can find the gradient of the perpendicular line, or the normal.

m1 × m2 = -1

Replace m1 with 1/2

1/2 × m2 = -1

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Substitute values into

y-y1=m (x-x1)

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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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3 years ago

Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa

melomori [17]

Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

$P = P_{1} + P_{2} + P_{3} + P_{4}$

$P_{1}$ is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

$P_{1} = 0.07*0.30 = 0.021$

$P_{2}$ is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

$P_{2} = 0.1*0.25 = 0.0215$

$P_{3}$ is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

$P_{3} = 0.12*0.40 = 0.048$

$P_{4}$ is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

$P_{3} = 0.05*0.05 = 0.0025$

$P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093$

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

4 0

3 years ago