<u>1 mole of oxygen.</u>
Answer:
solution given:
![2Na+O_2=Na_2O_2\\2mole\:\: 1mole \:\: 1mole](https://tex.z-dn.net/?f=2Na%2BO_2%3DNa_2O_2%5C%5C2mole%5C%3A%5C%3A%201mole%20%5C%3A%5C%3A%201mole)
according to the above reaction,1 mole of oxygen is required to react with 2 moles of sodium to form sodium peroxide.
Explanation:
Answer:
8.2×10¯⁵ L
Explanation:
82 μL.
We can convert 82 μL to L by doing the following:
To convert from microlitre (μL) to litre(L), we need to know how many microlitre (μL) that makes up a litre (L)
Recall:
1 μL = 1×10¯⁶ L
Therefore,
82 μL = 82 μL × 1×10¯⁶ L/1 μL
82 μL = 8.2×10¯⁵ L
Therefore, 82 μL is equivalent to 8.2×10¯⁵ L
Answer:
Q = 143,921 J = 143.9 kJ.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:
![Q=m*\Delta _{vap}H](https://tex.z-dn.net/?f=Q%3Dm%2A%5CDelta%20_%7Bvap%7DH)
Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:
![Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ](https://tex.z-dn.net/?f=Q%3D63.7g%2A2259.36J%2Fg%5C%5C%5C%5CQ%3D143%2C921J%3D143.9kJ)
Regards!