Answer:
Based on compounds given, NO reaction occurs
Explanation
The compounds should exchange ions to generate a driving force that pulls the reaction to completion. => Example ...
The Molecular Equation is ...
NH₄Cl(aq) + AgNO₃(aq) => NH₄NO₃(aq) + AgCl(s)
Silver chloride forms in this reaction as a solid precipitate because of its low solubility and is the 'Driving Force' of the reaction. Driving Force is a more stable compound than any on the reactant side and when formed leaves the reaction system as a solid ppt, liquid weak electrolyte (i.e., weak acid or weak base) or a gas decomposition product of a weak electrolyte.
The Ionic Equation is ...
NH₄⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) => NH₄⁺(aq) + NO₃⁻(aq) + AgCl(s)
This shows all ions from reaction plus the Driving Force of the reaction.
The Net Ionic Equation is ...
Ag⁺(aq) + Cl⁻(aq) => AgCl(s)
The Net Ionic Equation shows only those ions undergoing reaction. The NH₄⁺ and NO₃⁻ ions are 'Spectator Ions' and do not react.
Attached is a reference sheet for determining the Driving Force of a Metathesis Double Replacement Reaction. Suggest reviewing acid-base theories and the products of decomposition type reactions.
Potential energy is stored energy. Kinetic energy involves movement.
If a ball is on the top of a hill, it has the most potential energy on the very top of the hill. The kinetic energy is also 0 at this point.
If the ball rolls down the hill, potential energy decreases while kinetic increases.
simple example
2.43 kilograms is equal to 2430 grams because 1 kilogram is equal to 1000 grams.
Answer:
Strontium
Explanation:
The atomic number of strontium is 38.
It has 38 electrons.
It is alkaline earth metal. It has two valance electrons.
Strontium loses its two electrons and form cation with +2 charge.
Electronic configuration;
Sr₃₈ = [Kr] 5s²
The valance electrons present in 5s are lost by strontium atom and form Sr⁺² cation.
it is yellowish-white metal.
It is highly reactive.
It form salt with halogens.e.g
Sr + Br₂ → SrBr₂
IT react with oxygen and form oxide.
2Sr + O₂ → 2SrO
this oxide form hydroxide when react with water,
SrO + H₂O → Sr(OH)₂
With nitrogen it produced nitride,
3Sr + N₂ → Sr₃N₂
With acid like HCl,
Sr + 2HCl → SrCl₂ + H₂