(3) <span>electronegativities of the bonded atoms in a molecule of the compound is the correct answer.
The compound is nonpolar when</span> electronegativity is from 0 to 0.5, polar when electronegativity is from 0.5 to 1.7, and ionic when electronegativity is larger than 1.7.
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Answer:GASEOUS, LOWERING ,EMITTED AS HEAT, DOWN,DO NOT RELEASE,DECREASES,NEGATIVE.
Explanation: Filling the blanks gives
Lattice energy is associated with forming a crystalline lattice of alternating cations and anions from the _GASEOUS___________ ions.
Because the cations are positively charged and the anions are negatively charged, there is a LOWERING of potential- as described by Coulomb's law-when the ions come together to form a lattice energy.That energy is EMITTED AS HEAT when the lattice forms.
As the ionic radii increases as you move DOWN a group, ions cannot get as close to each other and therefore DO NOT RELEASE as much energy when the lattice forms. Thus the lattice energy DECREASES (becomes less) NEGATIVE as the radius increases.
The above gives the definition of Lattice Energy and how it relates to atomic and ion charge.
8.24g
Explanation:
Given parameters;
Mass of NH₃ = 10g
Unknown:
Mass of N₂ = ?
Solution:
Reaction equation:
N₂ + 3H₂ → 2NH₃
Step 1: Convert 10.0 g of NH₃ into moles of NH₃
number of moles = 
molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles =
= 0.59mole
Step 2: Convert the moles of NH₃ calculated in Step 1 into moles of N₂
1 mole of N₂ produced 2 mole of NH₃
0.59 moles of ammonia would be formed by
mole = 0.29mole of N₂
Step 3: Convert the moles of N₂ calculated in Step 2 into grams of N₂.
Mass of N₂ = number of moles x molar mass
Molar mass of N₂ = 14 x 2 = 28g/mol
Mass of N₂ = 0.29 x 28 = 8.24g
learn more:
Number of moles brainly.com/question/1841136
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Answer:
2.18x10^-9 M
Explanation:
From the question given,
Hydrogen ion concentration, [H+] = 4.59x10^-6 M
Hydroxide ion, [OH-] =?
The hydroxide ion concentration, [OH-] in the solution can be obtained as follow:
[H+] x [OH-] = 1x10^-14
4.59x10^-6 x [OH-] = 1x10^-14
Divide both side by 4.59x10^-6
[OH-] = 1x10^-14 / 4.59x10^-6
[OH-] = 2.18x10^-9 M