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Ksivusya [100]
2 years ago
5

The pair of polygons is similar. Find the value of x

Mathematics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

C i think

Step-by-step explanation:

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How many do all triangles equal
Ratling [72]
If we are talking about degrees they should equal 180
8 0
2 years ago
What is the slope of the following 12x - y = 30<br> -12
antiseptic1488 [7]

Answer:

12

Step-by-step explanation:

Rearrange into the form y = mx + c, where m is the slope.

12x - y = 30

y = 12x - 30

m = 12

4 0
3 years ago
20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
Yeah 82,300,000 scientific notation
IceJOKER [234]

Answer:

Dear user,

Answer to your query is provided below

82300000 in scientific notation = 8.23 × 10^7.

Step-by-step explanation:

Scientific notation is a way of writing very large or very small numbers. A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10. For example, 650,000,000 can be written in scientific notation as 6.5 ✕ 10^8.

4 0
3 years ago
Read 2 more answers
Please cancel. I do not have the money to continue the subscription. Thanks
Andrej [43]

Step-by-step explanation:

why is it difficult to make decision in education

4 0
2 years ago
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