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Brrunno [24]
2 years ago
8

PLEASSEE HHEELLPP ITS DUE SOON

Mathematics
1 answer:
IgorC [24]2 years ago
5 0

Answer:

the answers are in the photo

Step-by-step explanation:

you can solve for the range and domain by making an x and y chart, listing the x values, then using the graph in the first part to find the y values with the slope. for the matching part, you can find what the slope is by seeing how much the x values increase and same with the y values. then match the graph with wahtever equation has that slope. I hope this helps

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The rectangle below is enlarged using a scale factor of 1.5. What will be the new length and width of the rectangle?
Likurg_2 [28]

Answer: length = 4.5 m, width = 3 m

Step-by-step explanation:

When a shape is enlarged using a scale factor, you simply multiply each of the sides by the scale factor.

length = 3 * 1.5 = 4.5 m

width = 2 * 1.5 = 3 m

5 0
3 years ago
Evaluate the expression if a = 2, b = −3, c = −4, h = 6, y = 4, and z = −1.
scZoUnD [109]

Step-by-step explanation:

Hope it helps. Please mark as brainliest.

6 0
3 years ago
Find the slope of a line that passes through (-2,1) and (4,9)
melamori03 [73]

Answer:

m = 4/3

Step-by-step explanation:

To find the slope of a line use the formula, where "m" means slope:

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

*You don't need to show this part on paper*

Choose which point you want to be point 1 and point 2. Remember the points are written (x, y).

Point 1: (-2, 1)       x₁ = -2  y₁ = 1

Point 2: (4, 9)      x₂ = 4   y₂ = 9

Substitute the coordinates into the formula:

*Show this part on paper*

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

m=\frac{9-1 }{4-(-2) }         Simplify

m=\frac{8 }{6 }                Reduce by dividing by 2

m=\frac{4 }{3 }               Slope

The slope of the line is 4/3

8 0
3 years ago
5. Does the following table represent a function?*
Arturiano [62]

Answer:

Yes

Step-by-step explanation:

Yes, because each x has one specific y.

7 0
3 years ago
Read 2 more answers
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
2 years ago
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