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3 years ago

If AC = x + 5 and AB = 3x - 1... what is the length of BC?

1 answer:

4 0

If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10 |subtract 2 from both sides
3x = 5x - 12 |subtract 5x from both sides
-2x = -12 |divide both sides by (-2)
x = 6

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Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

4 0

3 years ago

3x-2>4<br> What’s the answer

Oxana [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

(50 points) URGENT <br> Can someone help me with this problem?

34kurt

Answer:

bit.^{}ly/3a8Nt8n these are the answers

7 0

3 years ago

Find the distance between the points L(7,-1) and M(-2, 4).

zysi [14]

Answer:

The answer is

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

$|LM| = \sqrt{ ({7 + 2})^{2} + ( { - 1 - 4})^{2} } \\ = \sqrt{ {9}^{2} + ({ - 5})^{2} } \\ = \sqrt{81 + 25} \\ = \sqrt{106} \: \: \: \: \: \: \: \\ = 10.29563014...$

We have the final answer as

$\sqrt{106} \: \: \: or \: \: \: 10.3 \: \: \: \: units$

Hope this helps you

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3 years ago

Help! please!!!!!! look at photo :))

JulsSmile [24]

Hey there!

We know that Danielle earns $10 per hour, so muliply that by 3 and get 30.

Because Danielle works an extra half an hour, divide 10 by 2 and get 5.

Danielle earns $35 in 3 hours and a half.

Hope this helps! Please mark me as brainliest!

Have a wonderful day :)

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3 years ago