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3 years ago

(8x- 1) (11X - 25) (15y - 48)

Mathematics

1 answer:

Leona [35]3 years ago

3 0

Answer:

1320x^2y−4224x^2−3165xy+10128x+375y−1200

Step-by-step explanation:

(8x−1)(11x−25)(15y−48)

=((8x−1)(11x−25))(15y+−48)

=((8x−1)(11x−25))(15y)+((8x−1)(11x−25))(−48)

=1320x2y−3165xy+375y−4224x2+10128x−1200

=1320x^2y−4224x^2−3165xy+10128x+375y−1200

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Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

$\sqrt{55x} = \sqrt{5 \times 11 \times x}$

the smallest value of x to make 55x a perfect square is....

$x = 11 \times 5 = 55$

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A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle t

ahrayia [7]

Answer:

10.67 m

Step-by-step explanation:

Velocity is given as;

v(t) = t² − t − 6

To get the distance, we will integrate the velocity equation.

x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t

Thus, from t=0 seconds to t=4 seconds., we have;

(t³/3) - (t²/2) - 6t between 0 and 4.

Thus;

Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]

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Distance can't be negative and so we take the absolute value which is 10.67 m

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3 years ago

(8x- 1) (11X - 25) (15y - 48) ​

(8x- 1) (11X - 25) (15y - 48)