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2 years ago

(8x- 1) (11X - 25) (15y - 48)

Mathematics

1 answer:

Leona [35]2 years ago

3 0

Answer:

1320x^2y−4224x^2−3165xy+10128x+375y−1200

Step-by-step explanation:

(8x−1)(11x−25)(15y−48)

=((8x−1)(11x−25))(15y+−48)

=((8x−1)(11x−25))(15y)+((8x−1)(11x−25))(−48)

=1320x2y−3165xy+375y−4224x2+10128x−1200

=1320x^2y−4224x^2−3165xy+10128x+375y−1200

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2 years ago

If you had to subtract 426 from 913 how many times would you need to regroup ?

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<u />487 would be your total but your question is how many times we would have to regroup, so.

<u />

First, you would have to borrow from the 1 because 3 is smaller then 6. Second, you would have to borrow from the 9 because you can't take 2 from 0. So there you would have to regroup twice to work this problem.

Hope that helps you. :-)

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3 years ago

Read 2 more answers

(8x- 1) (11X - 25) (15y - 48) ​

(8x- 1) (11X - 25) (15y - 48)