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Elena L [17]
3 years ago
14

Order the number 7/4, 1.6, 1 5/8, 1.65 from least to greatest.

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0
Here are the numbers from least to greatest     
1.6,1.65,15/8,7/4
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The cost, in dollars, of a one-day car rental, is given by C (x) = 31 + 0.18x, where x is the number of miles driven. In this fu
julia-pushkina [17]

Answer:

hi

Step-by-step explanation:

the function is c(x) = 31 + 0.18*x

where $31 is a fixed cost, and $0.18 is the cost per mile drive (where the number of miles driven)

So the fixed cost, $31, is the cost per day of rent (this price does not depend on the number x), and the linear cost, $0.18, is the cost per mile driven (because this number is multiplied by x in the function), then the right answer is B: "$31 is the cost per day to rent the car and $0.18 is the cost per mile."

5 0
3 years ago
2 ways to write y divided by three in algebra expression
JulijaS [17]

Answer:

y/3. 1/3y

Step-by-step explanation:

1/3y is y/3 because 1*y=y

7 0
3 years ago
The point Z(5, -3) is rotated 270° clockwise around the origin. What are the coordinates of the resulting point, Z′?
g100num [7]

Answer:

(3, - 5 )

Step-by-step explanation:

Under a clockwise rotation about the origin of 270°

a point (x, y ) → (- y, x ), hence

Z(5, - 3 ) → Z'(3, - 5 )

4 0
3 years ago
Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
PLEASE HELP!!!!!<br> WILL MARK BRAINLIEST!!!!
Viktor [21]

Answer:

NOT a function

Step-by-step explanation:

a function exists when every unique x input has a unique y output.

here every x less than 0 has two y values.

3 0
3 years ago
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