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lara31 [8.8K]
3 years ago
5

turn the improper fraction into a mixed number c)45/7 d)20/3 turn these numbers in to a mixed number please help

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0
A mixed number looks like this: a(b/c)
The improper fraction currently looks like this: (ab/c)
Round the numerator to something you can divide by the denominator. For example, 45 would be rounded to 42. 42/7=6. 6 would be the whole number.
45-42=3. 3/7 is the new fraction.
So the answer for c is 6(3/7)
Do you know how to do d?
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Step-by-step explanation:

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Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

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Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

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The deduction is based on the definition of independent random variables, we can do this:

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And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

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3 years ago
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Answer:

358

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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