Answer:
Angle JKN = 77°
Step-by-step explanation:
for our ease, let angle JKL = a , angle LKN = b, angle NKM = c
Since angle a + b + c = 105° (angle JKM = 105°) --------------------- (1)
but we are also given that angle b + c (angle LKM) is equal to 56°
using it in equation (1), we get
a + 56° = 105°
a = 49°
We are given that the line KN bisects the angle (b + c)
Hence, b = c
angle b (LKN) = angle c (NKM) = 28°
Angle JKN = angle a + b
Angle JKN = 49 + 28
Angle JKN = 77°
Kindly Mark Brainly, Thanks!
