Answer:
the range is -5>-9
the domain is 44
Step-by-step explanation:
Answer:
So Cody increase his savings by 87.5%
Step-by-step explanation:
We are given Cody's original savings = $40
We are given his new savings total = $75
Now, in order to find out the percentage we have to first find out by how much did he increase his savings:
Increase in savings = $75 - $40 = $35
So now we have the increase in savings we can find out the percentage:

Now we plug in our values that we found:

So Cody increase his savings by 87.5%
Answer:
Claim : Jump distance is less than 16 feet.
A ) 
n = 19
Since n <30 we will use t test
The mean distance of the sample jumps is 13.2 feet. i.e. x = 13.2 feet
The standard deviation of her jump distance is 1.5 ft i.e. s = 1.5
Formula : 
Substitute the values:
B) 

degree of freedom df = n-1 = 19-1 = 18


t critical > t statistics
So, we accept the null hypothesis
C) So, the claim is wrong that ump distance is less than 16 feet.
Hence long jump distance must be greater than or equal to 16
<u><em>Division and Multiplication.</em></u>
<u><em>Division is to check.SO multiplication is the correct answer.</em></u>
Since each trial has the same probability of success,
Let, <span><span><span>Xi</span>=1</span></span> if the <span><span>i<span>th</span></span></span> trial is a success (<span>0</span> otherwise). Then, <span><span>X=<span>∑3<span>i=1</span></span><span>Xi</span></span><span>X=<span>∑<span>i=1</span>3</span><span>Xi</span></span></span>,
and <span><span>E[X]=E[<span>∑3<span>i=1</span></span><span>Xi</span>]=<span>∑3<span>i=1</span></span>E[<span>Xi</span>]=<span>∑3<span>i=1</span></span>p=3p=1.8</span><span>E[X]=E[<span>∑<span>i=1</span>3</span><span>Xi</span>]=<span>∑<span>i=1</span>3</span>E[<span>Xi</span>]=<span>∑<span>i=1</span>3</span>p=3p=1.8</span></span>
So, <span><span>p=0.6</span><span>p=0.6</span></span>, and <span><span>P{X=3}=<span>0.63</span></span><span>P{X=3}=<span>0.63</span></span></span>
I thought what I did was sound, but the textbook says the answer to (a) is <span>0.60.6</span> and (b) is <span>00</span>.
Their reasoning (for (a)) is as follows: