Answer:
y=12x-125
Step-by-step explanation:
y=12x+3
parallel lines have same slopes,
y-y1=m(x-x1)
y-(-5)=12(x-10)
y+5=12x-120
y=12x-120-5
y=12x-125
t= 86degree 86+86+30+Qdegre= 360 degree add Q×2 that's all
Answer:
a c e ace ace ace ace ace ace ace
If the polynomial in the numerator is a higher degree than the denominator , there is no horizontal asymptote
Begin with cos(θ) = 5/13, θ in Quadrant IV
you should distinguish the 5-12-13 right-angled triangle
and then cosØ = adjacent/hypotenuse
x = 5, r = 13 , y = -12, since Ø is in IV
and sinØ = -12/13
also tan(ϕ) = −√15 = -√15/1 = y/x and ϕ is in II,
y = √15 , x = -1
r^2 = x^2 + y^2 = 15+1 = 16
r = 4
sinϕ = √15/4 , cosϕ = -1/4
you must know that:
cos(θ − ϕ) = cosθcosϕ + sinθsinϕ
= (5/13)(-1/4) + (-12/13)(√15/4)
= -5/52 - 12√15/52
= (-5-12√15)/52
