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adelina 88 [10]
3 years ago
8

What is that value is (5)squared

Mathematics
2 answers:
Nat2105 [25]3 years ago
8 0
5 squared is 5*5 which is 25\
Arisa [49]3 years ago
6 0
5 squared is the same as 5^2 which is 5*5. The answer is 25.
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Interior is 144
(x-2)180 then divide it by x
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A sack has 1 apple and 16 oranges You pick one fruit. what is the chance its a apple ?
lubasha [3.4K]
It’s c because there’s only one apple
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How many pounds of candy that cells for $0.66 per Ib must be mixed with candy that sells for $1.31 per Ib to obtain 9 Ib of a mi
faltersainse [42]

Answer:  \frac{306}{65} pounds

Step-by-step explanation:

Let x pounds of $ 0.66 per lb candies mixed with y pounds of $ 1.31 per lb candies to obtain 9 lb of $ 0.97 per lb candies,

Hence, we can write,

x + y = 9 ------- (1)

And, 0.66 of x + 1.31 of y = 0.97 of (x + y)

⇒ 66 x + 131 y = 97 (x+y)

⇒ 66 x +131 y - 97 x - 97 y = 0

⇒ -31 x + 34 y = 0  ------(2)

By solving equation (1) and (2)

We get,

x=\frac{306}{65} and y=\frac{279}{65}

Hence, the quantity of 0.66 per lb candies = \frac{306}{65}  pounds

7 0
2 years ago
Find the solution to the initial value problem
Karo-lina-s [1.5K]

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

(m + 4)² = 0

m = -4 twice

The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

3 0
3 years ago
a store is giving away $10 coupons to every 7th person to enter the store and a $25 coupon to every 18th person too emter the st
almond37 [142]
7,14,21,28,35,42,49,56,63,70,77,84,91,98,105,112,119,126
18,36,54,72,90,108,126 

So the first person to get both of them is the 126th person
3 0
3 years ago
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