Answer:
Explanation: Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)
Sublimation;When anything solid turns into a gas without first becoming liquid, <span> When the surface layer of snow or ice turns into fog or steam without melting, </span>
Answer:
A) 2.27 grams of tungsten trioxide must be needed to prepare 1.80 g of tungsten.
B)To prepare 1.80 g of tungsten we will need 0.0587 grams of hydrogen gas.
Explanation:
A) Mass of tungsten prepared = 1.80 g
Moles of tungsten =
According to reaction, 1 mol of tungsten is obtained from 1 mole of tungsten trioxide.
Then 0.009783 moles of tungsten will be obtained from:
of tungsten trioxide
Mass of 0.009783 moles of tungsten trioxide :
0.009783 mol × 231.8 g/mol = 2.27 g
2.27 grams of tungsten trioxide must be needed to prepare 1.80 g of tungsten.
B) According to reaction,1 mol of tungsten is produced by 3 moles of hydrogen gas
Then 0.009783 moles of tungsten are produced by :
Mass of 0.02935 moles of hydrogen gas:
0.02935 mol × 2 g/mol =0.0587 g
To prepare 1.80 g of tungsten we will need 0.0587 grams of hydrogen gas.
The chemical reactions necessary are unable to occur without the addition of different ingredients
Answer:
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