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chubhunter [2.5K]
3 years ago
6

All of the food that we eat, liquids that we drink and medications that we take are

Chemistry
1 answer:
kirill115 [55]3 years ago
3 0

A) Chemicals

(I'm pretty sure)

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A fruit-and-oatmeal bar contains 142 nutritional Calories. Convert this energy to calories
madreJ [45]

Answer:

a fruit and oatmeal bar contains 142000 calories.

A nutritional calorie, or kilocalorie, is equal to 1000 calories.

E = 142 kcal · 1000 cal/kcal.

E = 142 000 cal.

Calorie (cal), or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.

One small calorie is approximately 4.2 joules.

A calorie is a unit of energy.

Explanation:

hope it helps  :)

4 0
3 years ago
What are 3 types of mutations
mote1985 [20]

1- Base substitutions.

2- Deletions.

3- Insertions.

6 0
3 years ago
Read 2 more answers
An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons. What is the name of this element?
DedPeter [7]

Given :

An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons.

To Find :

The name of this element.

Solution :

We know, element with atomic number ( number of protons ) 12 and valance electrons is Magnesium.

Now, isotope of magnesium of proton with 14 neutrons is Mg-16 .

Therefore, name of element is Mg-16 .

Hence, this is the required solution.

5 0
3 years ago
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?​
Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

Fraction remaining = 3.13%

3 0
3 years ago
An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d = 13.53 g/cm3). What i its volu
Tasya [4]

Answer:

a) Volume of vial= 9.626cm3

b) Mass of vial with water = 62.92 g

Explanation:

a) Mass of empty vial = 55.32 g

Mass of Vial + Hg = 185.56 g

Therefore,

mass\ of\ Hg = 185.56-55.32 = 130.24 g

Density of Hg = 13.53 g/cm3

Volume\ of\ vial = Volume\ of\ Hg = \frac{Mass}{Density} \\\\= \frac{130.24g}{13.53g/cm3} = 9.626 cm3

b) Volume of water = volume of vial = 9.626 cm3

Density of water = 0.997 g/cm3

Mass\ of\ water = Density*volume = 0.997g/cm3*9.626cm3=9.60 g\\\\Total\ Mass\ of\ vial = Empty\ vial + mass\ of\ water\\= 53.32+9.60= 62.92g

3 0
3 years ago
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