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Answer:
Explanation:
<u>1) Rate law, at a given temperature:</u>
- Since all the data are obtained at the same temperature, the equilibrium constant is the same.
- Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:
r = K [A]ᵃ [B]ᵇ
<u>2) Use the data from the table</u>
- Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s
Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0
- Use the first and second set of data to find the exponent a:
r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s
r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s
Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]
2ᵃ = 2 ⇒ a = 1
<u>3) Write the rate law</u>
This means, that the rate is independent of reactant B and is of first order respect reactant A.
<u>4) Use any set of data to find K</u>
With the first set of data
- r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹
Result: the rate constant is K = 0.167 s⁻¹
<u>Answer:</u> 1.0 kilograms.
<u>Explanation:</u>
One kilogram is equal to a thousand grams.
Supposing x to be the number of kilograms equal to one thousand and eight grams, we can write it as:
1 kg = 1000 grams
x kg = 1008 grams
To solve for x, we can simply divide 1008 grams by 1000 thousand grams to get the answer.
x = 1008 / 1000
x = 1.008
Rounding this value to the nearest tenth, it will become 1.0 kilograms.
Answer:
The volume is 19.7 mL
Explanation:
<u>Step 1</u>: Given data
Pressure at sea level = 1.00 atm
Pressure at 50 ft = 2.47535 atm
kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm
Molarity (M) = kH x P
<u>Step 2</u>: Calculate molarity
M at sea level:
M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L
M at 50ft:
M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L
We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.
13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L
Step 3: Calculate volume
P*V=nRT
with P = 1.00 atm
with V = TO BE DETERMINED
with n = 8.04*10^-4 mol/L *1L = 8.04*10^-4
with R= 0.0821 atm * L/ mol *K
with T = 25 °C = 273+25 = 298 Kelvin
To find the volume, we re-organize the formula to: V=nRT/P
V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml
The volume is 19.7 mL
Iron has TWO valence electrons......
