The answer is 30 because u have to round 73 to 70 and 13 to 10 and in the middle of 10and 70 is 30
Answer:
I can't answer your question because I can't see what boxes your talking about
Answer: 60 pages left.
Step-by-step explanation:
Let the number of pages in the book be x.
As per given, we have
![\dfrac14x+20=\dfrac13x\\\\\Rightarrow\ \dfrac{1}{3}x-\dfrac14 x=20\\\\\Rightarrow\ \dfrac{4-3}{12}x=20\\\\\Rightarrow\ \dfrac1{12}x=20\\\\\Rightarrow x=20\times12\\\\\Rightarrow x=240](https://tex.z-dn.net/?f=%5Cdfrac14x%2B20%3D%5Cdfrac13x%5C%5C%5C%5C%5CRightarrow%5C%20%5Cdfrac%7B1%7D%7B3%7Dx-%5Cdfrac14%20x%3D20%5C%5C%5C%5C%5CRightarrow%5C%20%5Cdfrac%7B4-3%7D%7B12%7Dx%3D20%5C%5C%5C%5C%5CRightarrow%5C%20%5Cdfrac1%7B12%7Dx%3D20%5C%5C%5C%5C%5CRightarrow%20x%3D20%5Ctimes12%5C%5C%5C%5C%5CRightarrow%20x%3D240)
of total book =
Pages left = 240-180
= 60
Hence, 60 pages left.
Let y =
![\frac{x}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20)
+ 3 be line₁
And the perpendicular angle be line₂
If a line is perpendicular to another, then the product of their gradients is -1, which means that the gradient of line₂ would be the negative reciprocal of line₁
Based on that, if the gradient of line₁ is
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
then, the gradient of line₂ is - 2.
Now by using the point-slope form y - y₁ = m ( x - x₁)
If line₂ passes through the line (1,8) and have gradient -2,
then by exploiting the point-slope form y - 8 = -2 (x - 1)
∴ equation of the ine perpendicular to y =
![\frac{x}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20)
+ 3 would be
y = -2x + 10
Answer:
no
Step-by-step explanation:
2(1) -3(-3) = 6
2+9=6
11=6
this is not true because 11 does not equal 6