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Answer:
200 mg sodium is in 1 oz of chips and 50 mg sodium is in 1 cup of soda.
Step-by-step explanation:
Let x mg sodium is in 1 oz of chips and and y mg is in 1 cup of soda.
∵ Bryan ate 3 oz of chips and drank 2 cups of soda for a total of 700 mg of sodium.
i.e. 3x + 2y = 700 --------(1),
Jadyn ate 1 oz of chips and drank 3 cups of soda for a total of 350 mg of sodium.
i.e. x + 3y = 350 ---------(2),
Equation (1) - 3 × equation (2),
We get,
2y - 9y = 700 - 1050
-7y = -350
From equation (1),
3x + 2(50) = 700
3x + 100 = 700
3x = 700 - 100
3x = 600
Hence, 200 mg sodium is in 1 oz of chips and 50 mg sodium is in 1 cup of soda.
Answer:
x = - , x =
Step-by-step explanation:
to find the points of intersection equate the 2 equations , that is
7x - 15 = 10 + 12x - 6x² ( subtract 10 + 12x - 6x² from both sides )
6x² - 5x - 25 = 0 ← factor the quadratic on left side
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × - 25 = - 150 and sum = - 5
the factors are - 15 and + 10
use these factors to split the x- term
6x² - 15x + 10x - 25 = 0 ( factor the first/second and third/fourth terms )
3x(2x - 5) + 5(2x - 5) = 0 ← factor out (2x - 5) from each term
(2x - 5)(3x + 5) = 0
equate each factor to zero and solve for x
3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = -
2x - 5 = 0 ⇒ 2x = 5 ⇒ x =