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Diano4ka-milaya [45]
3 years ago
14

Suppose you have two identical-looking metal spheres of the same size and the same mass. One of them is solid; the other is holl

ow. Describe a simple test that you could do to determine which is which.
Chemistry
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

We, apply equal torque to both spheres and measure their final angular acceleration.

Explanation:

The moment of Inertia of solid sphere will be (2/5)mr²

The moment of Inertia of hollow sphere will be (2/3)mr²

Thus, the moment of inertia of inertia of hollow sphere is greater than that of the solid sphere. Since, the torque is equal to the product of moment of inertia and angular acceleration.

Therefore, we design a test such that we apply the same amount of torque to both the spheres. Due to greater amount of moment of inertia the hollow sphere will acquire high angular acceleration, while solid sphere will acquire low angular acceleration.

Hence, by the measurement of final angular acceleration, we can determine, which sphere is which.  

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What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall r
Sergeu [11.5K]
Answer:
             5 moles of electrons

Explanation:

The balance equation is as follow,

<span>                   5 Ag</span>⁺ + Mn⁺²<span> + 4 H</span>₂O    →<span>    5 Ag + MnO</span>₄⁻<span> + 8 H</span>⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
                         5 Ag⁺  +  5 e⁻    →    5 Ag

Oxidation of Mn:

                          Mn⁺²   →    MnO₄⁻  +  5 e⁻

Result:
          Hence 5 moles of Ag⁺ accepts 5 electrons from 1 mole of Mn⁺².
4 0
3 years ago
How is burning magnesium different than burning methane
olya-2409 [2.1K]

You can stop the burning of methane with water or carbon dioxide extinguishers but problems arise when you try to use this to stop the burning of the magnesium.

Explanation:

To burn magnesium (Mg) and methane (CH₄) you need to react them with oxygen:

2 Mg (s) + O₂ (g) → 2 MgO + heat

CH₄ (g) + 2  O₂ (g) → CO₂ (g) + 2 H₂O (g) + heat

However at that temperatures magnesium (Mg) is able to react with water (H₂O) and carbon dioxide (CO₂).

Mg (s) + 2 H₂O (l) → Mg(OH)₂ (s) + H₂ (g)

2 Mg (s) + CO₂ (g) → 2 MgO (s) + C (s)

So the safe option to stop the burning of the magnesium is to limit the oxygen in the air.

we have used the following notations:

(s) - solid

(g) - gas

(l) - liquid

Learn more about:

combustion reactions

brainly.com/question/13824679

#learnwithBrainly

6 0
3 years ago
The vapor pressure of water is 1.00 atm at 373 K, and the enthalpy of vaporization is 40.68 kJ mol!. Estimate the vapor pressure
Yuki888 [10]

Answer:

The vapor pressure at temperature 363 K is 0.6970 atm

The vapor pressure at 383 K is 1.410 atm

Explanation:

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature T_1

P_2 = vapor pressure at temperature T_2

\Delta H_{vap} = Enthalpy of vaporization  

R = Gas constant = 8.314 J/mol K

1) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =363 K

T_2 = final temperature =373 K

P_2=1 atm, P_1=?

Putting values in above equation, we get:

\ln(\frac{1 atm}{P_1})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{363}-\frac{1}{373}]

P_1=0.69671 atm \approx 0.6970 atm

The vapor pressure at temperature 363 K is 0.6970 atm

2) \Delta H_{vap}=40.68 kJ/mol=40680 J/mol

T_1 = initial temperature =373 K

T_2 = final temperature =383 K

P_1=1 atm, P_2?

Putting values in above equation, we get:

\ln(\frac{P_2}{1 atm})=\frac{40680 J/mol}{8.314J/mol.K}[\frac{1}{373}-\frac{1}{383}]

P_2=1.4084 atm \approx 1.410 atm

The vapor pressure at 383 K is 1.410 atm

8 0
3 years ago
For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t
liberstina [14]

Explanation:

First Reaction;

Ca + ZnCl2 --> CaCl2 + Zn

Oxidized Reactant: Ca. There is increase in oxidation number from 0 to +2

Reduced Reactant: Zn. There is decrease in  oxidation number form +2 to 0

Second Reaction:

FeI2 + Mg --> Fe + MgI2

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Fe. There is decrease in  oxidation number form +2 to 0

Third Reaction;

Mg + 2AgNO3 --> Mg(NO3)2 + Ag

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Ag. There is decrease in  oxidation number form +1 to 0

5 0
3 years ago
Why do sea turtles rely on instincts more than mammals do?
qwelly [4]

Answer:

Mammals do not have instincts, so they must learn all their behaviors from their parents in order to survive.

Sea turtles must survive on their own, while mammals spend time with their parents and learn how to survive as they grow.

Sea turtles are less intelligent than mammals and, thus, cannot learn new behaviors from their parents.

Explanation:

6 0
2 years ago
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