1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WARRIOR [948]
3 years ago
6

What is the equation of the line that has a slope of -2 and passes through the point (-1, 2)?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

The answer is

<h2>y = 2x</h2>

Step-by-step explanation:

To find an equation of a line given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (-1 , 2) and the slope is - 2

The equation of the line is

<h3>y - 2 =  - 2(x + 1) \\ y - 2 =  - 2x - 2 \\ y =  - 2x - 2 + 2</h3>

We have the final answer as

<h3>y = 2x</h3>

Hope this helps you

You might be interested in
A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/20 for blue, 1/10 f
FromTheMoon [43]

Answer:

1/4

Step-by-step explanation:

4 0
3 years ago
What are the corresponding steps used to find the product of (2x + 1)(x + 1)?
Margarita [4]

Answer:

(2 x +1) ( x + 1)  = 2 x² + 3 x + 1

Step-by-step explanation:

The steops used to find the product of (2 x + 1) (x + 1) are

 =( 2 x )× x + (2 x) × 1 + x + 1

 = 2 x² + 2 x + x + 1

 = 2 x² + 3 x + 1

4 0
3 years ago
Please Help I don’t get this!!!☹️☹️Im gonna have a meltdown!
marta [7]

Answer:

Y = -5X

Step-by-step explanation:

<u>Don't</u><u> </u><u>have</u><u> </u><u>a</u><u> </u><u>meltdown</u><u>.</u><u> </u><u>It's</u><u> </u><u>not</u><u> </u><u>good</u><u> </u><u>for</u><u> </u><u>you</u><u>. </u><u>Glad</u><u> </u><u>to</u><u> </u><u>help</u><u> </u><u>you</u><u> </u><u>out</u><u>.</u> :)

7 0
1 year ago
Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
Describe the series of rigid transformations that maps pqs onto p’’’q ’’’s ’’’ .explain.
Masteriza [31]
It’s triangular your welcome hint q
7 0
2 years ago
Other questions:
  • Whats the answer to 0.7 squared 
    9·1 answer
  • How to write the simplest polynomial function of -2i and 1+i
    12·1 answer
  • Find X such that f(x)=0 for f(x)= -2x^2-x
    14·1 answer
  • The height of a box that carol is wrapping is 7 inches more than the width of the box. the length is 2 inches less than twice th
    7·1 answer
  • 0.0090 cubic micrometers in scientific notation.
    15·1 answer
  • What is the measure of the angle shown on the right
    13·2 answers
  • One of these scenarios represents a direct variation and one does not. How can you tell the difference? a) A large pizza with on
    8·1 answer
  • El tema es limites, por favor ayúdenme :C
    6·1 answer
  • Steve manages a skate park and he has been analyzing the attendance data. Steve finds that the number of visitors increases expo
    11·2 answers
  • Ellen,Krista,and Tori decide to buy their Mrs.Hannigan a fabulous pink flamingos purse The cost of the purse is $205 (what a ba
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!