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Ganezh [65]
4 years ago
5

How many three-digit numbers can you create using only the digits 6, 7, 8, and 9 if each digit cannot be repeated in any three-d

igit number (all digits must be different)?
Mathematics
1 answer:
svet-max [94.6K]4 years ago
8 0

Answer:

24

Step-by-step explanation:

We are solving for variation (without repitition)

n = 4 digits (6,7,8,9)

p = 3 digits no.

variation = nfactorial/ (n-p) factorial.

4x3x2x1/(4-3)factorial = 24/1

= 24.

there are 24 3-digit number you can select from 6,7,8,9 without having a recurring number.

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