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strojnjashka [21]
3 years ago
7

Classify the two given samples as independent or dependent. Sample 1: Pre-training blood pressure of 17 people Sample 2: Post-tr

aining blood pressure of 17 people a. dependent b. independent
Mathematics
1 answer:
Damm [24]3 years ago
7 0

Answer:

Sample  1 : independent

Sample  2 :   dependent

Step-by-step explanation:

From the question we are told that

   The  given date is  

                   Sample 1: Pre-training blood pressure of 17 people

                    Sample 2: Post-training blood pressure of 17 people

Now  Sample 1 is independent because  the Pre-training blood pressure of 17 people does not depend of Post-training blood pressure of 17 people

While  

        Sample 2  is  dependent because the Post-training blood pressure of 17 people is  dependent on the Pre-training blood pressure of 17 people

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Graphing Exponential Functions In Exercise, sketch the graph of the function.
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Answer:

The graph of the function f(x) = (1/2)^2x + 4 is attached as image below.

Analysis:

We have two intersection points in the graph

The function f(x) = (1/2)^2x + 4  intersects the y-axis at points (0,4)

The function f(x) = (1/2)^2x + 4  intersects the x-axis at points (-16,0)

f(x) is positive for x>-`16

f(x) is negative for x<-`16

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3 years ago
Which could be the area of one face of the rectangular prism? Select three options.
Anit [1.1K]

Answer:

24 cm squared

44 cm squared

66 cm squared

Step-by-step explanation:

6(4)= 24

11(4)= 44

11(6)= 66

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3 years ago
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What would this One be??
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Step-by-step explanation:

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3 years ago
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A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
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