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Lelu [443]
4 years ago
13

How many CO2 molecules are present in 12.47 L CO2

Chemistry
1 answer:
Ipatiy [6.2K]4 years ago
5 0
Take the given 12.47L then divide that by 22.4L then multiply it by 1 mole of CO2 then divide by 1 mole of CO2 then multiply by 6.02x10^23. Giving you an answer of 3.35^23 molecules of CO2
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The empirical formula of pyrogallol is C2H2O. Its molar mass is 126 g mol-1. What is the molecular formula?C4H4O2C2H6O3C6H6O3C2H
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Answer:

The molecular formula of pyrogallol is: C6H6O3

Explanation:

<u>Step 1:</u> Data given

Empirical formula of pyrogallol is C2H2O

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