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oee [108]
4 years ago
5

Write the complete balanced equation for the following reaction:

Chemistry
1 answer:
Assoli18 [71]4 years ago
6 0

Explanation:

An equation that consists of same number of atoms on both reactant and product side is known as a balanced chemical equation.

For example, C_{7}H_{6}O + O_{2} \rightarrow CO_{2} + H_{2}O

Number of atoms on reactant side are as follows.

C = 7

H = 6

O = 3

Number of atoms on product side are as follows.

C = 1

H = 2

O = 3

Therefore, to balance this chemical equation we multiply O_{2} by 8 on reactant side. Whereas we multiply CO_{2} by 7 and H_{2}O by 3 on product side.

Therefore, the balanced chemical equation will be as follows.

          C_{7}H_{6}O + 8O_{2} \rightarrow 7CO_{2} + 3H_{2}O

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Mass of CO₂ = 8.59 g  

Molar mass of CO₂ = 44 g/mol

Moles of CO₂ = Mass of CO₂ / Molar mass of CO₂ = 8.59 g  / 44 g/mol

                        = 0.1952 moles

Now there is 1 mole of C in 1 mole of CO₂

Therefore, moles of carbon = moles of CO₂ = 0.1952 moles

Mass of carbon = moles of C x  the atomic weight of C

                           = 0.1952 moles x 12 g/mol

                            = 2.3427 g

 Mass of H₂O = 3.52g  

Molar mass of H₂O = 18g/mol

Moles of H₂O =  3.52g /18g/mol = 0.1956 moles

Now there is 2 moles of H in 1 mole of H₂O

Moles of H = 0.1956 moles X 2  = 0.3912 moles

Mass of H = 0.3912 moles X atomic mass of H  

                 = 0.3912 moles X  1 g/mol = 0.3912 g

Mass of butyric acid = 4.30g  

Mass of O = mass of butyric acid - (mass of C + mass of H)

                  = 4.30 g - 2.3427 g - 0.3912 g = 1.5661 g

Moles of O = mass of O / atomic mass of O = 1.5661 g / 16 g/mol

                   = 0.0978 moles  

Divide by smallest mole to get the molar ratio  

C = 0.1952 moles/0.0978 moles  = 2

H =  0.3912 moles/0.0978 moles  = 4

O = 0.0978 moles  / 0.0978 moles  = 1

Empirical formula of butric acid is C₂H₄O  

Molecular formula of butric acid is C₄H₈O₂


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